Best Answer was from Sri
#include <stdio.h>
int add(int a, int b)
{
if (!a)
return b;
else
return add((a & b) << 1, a ^ b);
}
int main()
{
unsigned int a,b;
printf("Enter the two numbers: \n");
scanf("%d",&a);
scanf("%d",&b);
printf("Sum is: %d",add(a,b));
}
Regards,
Sri
>>>>>>>>>>>>>>>>>>>>
This looks like is a standard answer for this question - available in INTERNET
>>>>>>>>>>>>>>>>>>>>
KIRAN (sum= s[n]*pow(2,n) + sum;) – this uses + right???
>>>>>>>>>>>>>
#include<stdio.h>
#include<conio.h>
#include<math.h>
void main()
{
int n;
int a[10], b[10], c[10],s[10];
int x ,y ,sum=0;
c[0]= 0;
printf("enter any two numbers below 256 \n"); scanf("%d%d",&x,&y);
for(n=0;n<=9;n++)
{
a[n]= (x>>n)&1;
b[n]= (y>>n)&1;
s[n] = ((a[n])^(b[n]))^c[n];
c[n+1] = (a[n] & b[n])|(b[n] & c[n])|(c[n] & a[n]); }
for(n=9;n>=0;n--)
{
printf("%d\t",s[n]);
sum= s[n]*pow(2,n) + sum;
}
printf("\nsum = %d\n", sum);
}
thanks
kiran k
VIDYASAGAR
>>>>>>>>>>>
#include <stdio.h>
int add(int a, int b);
main()
{
int a,b;
printf("Enter the two numbers: \n");
scanf("%d",&a);
scanf("%d",&b);
printf("Sum of given 2 numbers is: %d",add(a,b));
}
int add(int a, int b)
{
if (!a)
return b;
else
{
int x = (a & b)<<1;
int y = a ^ b;
int z = add(x,y);
return z;
}
}
Thanks & Regards,
Vidyasagar
MANOHAR
>>>>>>>>
function prog()
a=40;
b=13;
ta=a;
tb=b;
v=0;
c=0;
clc
for i=1:16
s=bitxor(bitxor(bitand(a,1),bitand(b,1)),bitand(c,1));
v=v+s*(2^(i-1));
c=bitor(bitor(bitand(bitand(a,1),bitand(b,1)),bitand(bitand(a,1),bitand(c,1))),bitand(bitand(b,1),bitand(c,1)));
a=bitshift(a,-1);
b=bitshift(b,-1);
end
disp(v);
>>>>>>>>>>>>>>>>>
ABHINAY
>>>>>>>>>>>>>>>>
a=0;
x=(dec2bin(5))
y=(dec2bin(200))
t='';
if length(x)<8
for i=1:(8-length(x))
t(i)='0';
end
else
t='';
end
x=seqreverse([t x]);
t='';
if length(y)<8
for i=1:(8-length(y))
t(i)='0';
end
else
t='';
end
y=seqreverse([t y]);
for i=1:8
add(i)=bitxor(bitxor(str2num(x(i)),str2num(y(i))),a);
a=bitor(bitor(bitand(str2num(x(i)),str2num(y(i))),bitand(str2num(x(i)),a)),bitand(str2num(y(i)),a));
end
ad=seqreverse(add);
result=bin2dec(strrep(num2str(ad),' ',''))
>>>>>>>>>>>
SWETHA gave me logic but it is not acceptable.
>>>>>>>>>
BHIMSEN JOSHI
>>>>>>>>>>
#include<stdio.h>
void main()
{
int i;
int a = 255,b = 256;
int s=0,c=0,k, ai, bi ;
for(i=0;i<9;i++)
{
ai = ((a>>i)&1);
bi = ((b>>i)&1);
k = ((((ai^bi)^c))<<i);
s = s|k;
c = (ai&c) | (bi&c) | (ai&bi);
}
printf("%d",s);
}
From: bhimsen [mailto:bhimsen@cmcltd.com]
Sent: Thursday, July 17, 2008 11:30 AM
To: 'bhimsen'; 'bhimsen'; 'Manohar'; 'Srikanth P'; 'Abhniay CMC'; 'K_Suresh_CMC'; 'Kattamuri_CMC'; 'Kiran K_CMC'; 'Mani_CMC'; 'Meena_CMC'; 'Murali_CMC'; 'Pavan Kumar G'; 'Pavani Madhira CMC'; 'Rajani G'; 'rrk@cmcltd.com'; 'Sadalakshmi M CMC'; 'Sivakumar'; 'Sravan_B'; 'SravanKumar_GV'; 'sravanthi.batchu@cmcltd.com'; 'Sriraja kumari'; 'Swetha Tattari CMC'; 'Usha_CMC'; 'V.Satish_CMC'; 'Venkat Prasad D'; 'Venkata Krishna R'; 'Vidyasagar_CMC'; 'Vijay_CMC'; 'VLV Naresh Kumar'; 'Santosh Kumar'; 'Venkata Krishna R'; 'V.Satish_CMC'
Subject: RE: C question # 2 - send answers only to me
Importance: High
Is every one busy or cannot solve the simple problem?
None of the team members answered it correctly & completely.
I was thinking it is a 15 mins problem.
I received only one answer from Kiran.
From: bhimsen [mailto:bhimsen@cmcltd.com]
Sent: Wednesday, July 16, 2008 1:06 PM
To: 'bhimsen'; 'Manohar'; 'Srikanth P'; 'Abhniay CMC'; 'K_Suresh_CMC'; 'Kattamuri_CMC'; 'Kiran K_CMC'; 'Mani_CMC'; 'Meena_CMC'; 'Murali_CMC'; 'Pavan Kumar G'; 'Pavani Madhira CMC'; 'Rajani G'; 'rrk@cmcltd.com'; 'Sadalakshmi M CMC'; 'Sivakumar'; 'Sravan_B'; 'SravanKumar_GV'; 'sravanthi.batchu@cmcltd.com'; 'Sriraja kumari'; 'Swetha Tattari CMC'; 'Usha_CMC'; 'V.Satish_CMC'; 'Venkat Prasad D'; 'Venkata Krishna R'; 'Vidyasagar_CMC'; 'Vijay_CMC'; 'VLV Naresh Kumar'; 'Santosh Kumar'; 'Venkata Krishna R'; 'V.Satish_CMC'
Subject: C question # 2 - send answers only to me
Write a program to add two numbers <= 255
Constraint you cannot use arithmetic operators (+,-,*, /)
Use the Boolean operators (&, | ) and shift operators >>, << to achieve the result.
Regards,
Bhimsen joshi
--
At a certain point there is no difference between Magic and Science.
-Bhimsen Joshi
1 comment:
Include me too in the circulating list for such puzzles, At My gmail.
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