Given a 7 bit variable, convert into a 8 bit variable with ODD parity

Calculate ODD parity - excellent method

Here is a simple code example for 8 bit number, you can easily extend it to any bits you want. int

Oddparity(unsigned char p)

{

       p = p ^ (p > > 4);

       p = p ^ (p > > 2);

       p = p ^ (p > > 1);

       return p & 1;

}

>>> 

Rajini

>>> 

#include<stdio.h>

typedef char BYTE;

 

BYTE fnGetParity(BYTE bByte,BYTE bXor);

 

void main()

{

  BYTE bVal;

 

 scanf("%x",&bVal);

 

 BYTE bParity = fnGetParity(bVal,0);//fnGetParity(bVal,0);

 

 bVal = (bVal<<1)| (!bParity);

 

 printf("0x%x",bVal);

 

}

 

BYTE fnGetParity(BYTE bByte,BYTE bXor)

{

 

 if(bByte)

  fnGetParity(bByte>>1,(bByte&0x1) ^ bXor);

 else

   return bXor;

 

}

 

>>> 

Code found somewhere

>>> 

#define XYZ(data, shift)             (((data) >> (shift)) ^ (data))

 

void main ()

{

            int x = 0x11;

            printf("%x \n",(((XYZ(XYZ(XYZ(XYZ(x,8),4),2),1))&1)==0)?(x<<1)^1:x<<1);

 

}

>>>>> 

Manohar

>>>>> 

(Var>>1) | ~((var&1) ^ (var&2) ^ (var&4) ^ (var&8) ^ (var&16) ^ (var&32) ^ (var&64))

 

But this would be a hardcoded way!

 

>>>>> 

Murali

>>>>> 

#include <stdio.h>

#include <math.h>

void main()

{

     int c=0,i=0,a;

     printf("Enter value in decimal form (less than 127):");

     scanf("%x",&a);

 

     for(i=0;i<7;i++)

     {

          if((int(pow(2,i)) & a) !=0) 

          c=c+1;

          else

          c=c;

     }   

     a=a<<1;

     if (c%2==0 && c!=1)

     a=a+1; 

     printf("Encrypted Value with Odd Parity is %x\n",a);

}

 

>>> 

KIRAN

>>> 

#include<stdio.h>

void main()

{

 int s,c,n;

 printf("Enter a number lessthan 128\n");

 scanf("%x",&s);

 c=0;

 

 for(n=0;n<=6;n++)

  if(s>>n&1)

   c=c+1;

 

 c%2?n= (s|0<<8)<<1:n= ((s|0<<8)<<1)|1;

      

 printf("%x\n",n);

 

}

>>> 

VIDYASAGAR

>>> 

int main()

{

      int i;
      int a ,bit = 0,count = 0;
  
   printf("enter a number in hexa \n");
   scanf("%x",&a);

 

      for(i=0;i<6;i++)

      {
            bit = ((a>>i)&1);
               if(bit==1)
               {
                    count++;
                    bit = 0;
              } 

      }

   a = a<<1;
 
  if((count%2) == 0)//even parity
  {
   a= (a|1);
  }
   printf("%x\n",a);// our answer prints here

 

   return 0;

 

}//end of main

>>>> 

SADA

>>>> 

#include <stdio.h>

void main()
{
 int x,count=0;
 unsigned int a;

 printf("Enter the number: \n");

 scanf("%d",&a);
  
 for(x=0;x<=7;x++)
  
  (a&(0000001<<x))?count++:0 ;

 (float(count%2)==0)?(a=(a<<1)|00000001):(a=(a<<1)|00000000);

 

 printf("%d",a);

 

}

 

>>>> 

BHIMSEN

>>>> 

void main()

{

            int a = 0x55, r=1, od, i;

 

            for(i=0;i<7;i++)

                        r = ((a>>i)&1)^r;

 

            od = (a<<1)|r;

            printf("%x \n",od);

}

 

 

 Given a 7 bit variable, convert into a 8 bit variable with ODD parity

 

Example, if user inputs 0x11 then output shall be 0x23

                                  0x10 then output shall be 0x22

 

I am looking for most efficient program or MACRO

--
At a certain point there is no difference between Magic and Science.
-Bhimsen Joshi